sorry guys - i'm not convinced. the same amount of air is compressed over the same number of engine revs, end of story.
after drawing cylinder strokes out on a scrap of paper, i think i have sussed this for myself though...
consider a 4 cyl 4 stroke (straight 4):
- cyl1 - compression (valves closed, piston at top of cylinder)
- cyl2 - induction
- cyl3 - expulsion (exhaust valve open, piston at top of cylinder)
- cyl4 - ignition
the pattern repeats every 2 engine revs (not 4 as i said above) - compression, ignition, expulsion, induction (each cylinder does one of those)
now consider a V twin - the pistons will both be at the top of the cylinder simultaneously or the thing would shake apart hence:
- cyl1 - compression
- cyl2 - expulsion
half rev
- cyl1 - ignition
- cyl2 - induction
half rev
- cyl1 - expulsion
- cyl2 - compression
half rev
- cyl1 - induction
- cyl2 - ignition
half rev (repeat pattern)
in the twin, ignition
never occurs at the same time as compression, unlike in the 4 cylinder the compression (engine braking) on one cylinder will
always be counteracted by the ignition on another. hence 4's are smoother and have less pronounced engine braking.
that has to be the answer doesn't it?